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Hello,

One possible solution I think

UniDBGrid1.JSInterface.JSAssign('hideable', [False], UniDBGrid1.Columns[1].JSColumn);
UniDBGrid1.JSInterface.JSAssign('hideable', [True], UniDBGrid1.Columns[1].JSColumn);

 

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24 minutes ago, Sherzod said:

Hello,

One possible solution I think


UniDBGrid1.JSInterface.JSAssign('hideable', [False], UniDBGrid1.Columns[1].JSColumn);
UniDBGrid1.JSInterface.JSAssign('hideable', [True], UniDBGrid1.Columns[1].JSColumn);

 

Thank you very much Sherzod, I will adptar the code to always go through all my columns.

in my case I do not want any of my columns to have this option.

Thank you.

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9 minutes ago, Sherzod said:

Have you tried with?


uniDbGrid1.Columns[index].Menu.MenuEnabled := False;

 

Yes, my problem is that I do not create the columns, they are created dynamically when I open the dataset,

In this case, I'll need to create them to set this property of my column when I open the dataset, or at some point I'll have to run through the columns to make the command.

UniDBGrid1.JSInterface.JSAssign ('hideable', [False], UniDBGrid1.Columns [1] .JSColumn);

but I'm going to try to do the best I can here to stay cool ...

Thanks a lot for the help.

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4 hours ago, DEV_THS said:

I want to hide completely from the menu, I do not want to make this available to my user ...

For the grid header as a whole:

procedure TMainForm.UniFormCreate(Sender: TObject);
begin
  UniDBGrid1.JSInterface.JSConfig('enableColumnHide', [False]);
end;

 

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7 minutes ago, Sherzod said:

For the grid header as a whole:


procedure TMainForm.UniFormCreate(Sender: TObject);
begin
  UniDBGrid1.JSInterface.JSConfig('enableColumnHide', [False]);
end;

 

Perfect Sherzod, helped me too! so I do not compromise the performance of my application!

Thank you very much!

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