zanona Posted February 23, 2017 Share Posted February 23, 2017 How do you load an image into dbgrid without using the default directory? EX: OutImageURL: = 'files / sun.jpeg' goes right But if I switch to OutImageURL: = 'files / information / sun.jpeg' does not find the image itself the file being inside the folder! Procedure UniDBGrid1FieldImageURL(const Column: TUniDBGridColumn; const AField: TField; var OutImageURL: string); Thanks Zanona Quote Link to comment Share on other sites More sharing options...
Sherzod Posted February 23, 2017 Share Posted February 23, 2017 Hi, Can you clarify your question again?! * OutImageURL: = 'files/information/sun.jpeg' does not find the image itself the file being inside the folder! It should work Best regards. Quote Link to comment Share on other sites More sharing options...
zanona Posted February 23, 2017 Author Share Posted February 23, 2017 Exactly so! He does not find the picture! If I leave in the default "OutImageURL: = files /" works perfectly But if I include "OutImageURL: = files / information" do not think! Would it be a UNIGui bug? Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.